Question 264455
equation of a line with slope m and passing through the point (x1,y1) is given by


   (y-y1) = m(x-x1)

so equation of a line with a slope of -2/7 passing through the point (8,-7) is given by

    (y-(-7))=(-2/7)(x-8)

so  (y+7)=(-2/7)(x-8)

  7y+49 = -2x+16

  2x+7y+33=0