Question 264399
This is a mixture problem. Here is a table based on the given information.
acids . . . . . . .% . . . . . . . . .L . . . . . . . . .#L
pure. . . . . . . 100. . . . . . . x. . . . . . . . .100x
30. . . . . . . . . 30 . . . . . . . 22. . . . . . . .660
mixture. . . . . 45 . . . . . . .22+x . . . . . .990 + 45x
looking at the third column, we get
{{{100x + 660 = 990 + 45x}}}
subtract 660 and subtract 45x to get
{{{55x = 330}}}
divide to get
 {{{x = 6}}} liters