Question 264297
3a^2+a-10>0
we are using delta = b^2-4*a*c
my solution to this equation is [-5/2,3} the book says the solution is (-oo,-2)U(5/3,oo)
please help me find what I am doing wrong

3a^2+a-10>0
3a^2+6a-5a-10>0

3a(a+2)-5(a+2)>0

(a+2)(3a-5)>0