Question 263906
s^2 = t^-1 and t^1/4 = u^-1/3, then what is the value of s in terms of u
:
{{{s^2 = t^-1}}}
Reciprocal gets rid of the neg exponent
{{{s^2 = 1/t}}}
then
{{{s = sqrt(1/t)}}}
:
:
{{{t^(1/4) = u^(-1/3)}}}
Raise both side to the 4th power
{{{t = u^(-4/3)}}}; (this is -4/3 power)
:
Replace t in {{{s = sqrt(1/t)}}}
{{{s = sqrt(1/u^(-4/3)))}}}
Reciprocal gets rid of the neg exponent
{{{s = sqrt(u^(4/3)))}}}
We can also write the square root like this
{{{s = u^((4/3)*(1/2))}}}
which is
{{{s = u^(2/3))}}}; (exponent is 2/3)