Question 263977
Hint: If you square both sides of {{{sqrt(9x+67)=x+5}}} you get {{{9x+67=(x+5)^2}}}. FOIL out the right side to get {{{9x+67=x^2+10x+25}}}



From there, get every term to one side to get {{{x^2+x-42=0}}}. Now either factor or use the quadratic formula to solve for 'x'. Don't forget to check your answers by plugging them back into {{{sqrt(9x+67)=x+5}}}