Question 263934
two congruent squares touch at one corner. One side of the square measures 3 cm. The triangle created from two of the common sides is a right triangle. Find the area (to the nearest tenth) of the entire figure.

Area of one square = 3 cm * 3 cm = 9 cm^2
Area of both squares = 2 * 9 cm^2 = 18 cm^2
Area of Triangle = 1/2 * base * height = 1/2 * 3 cm * 3 cm= 3/2 * 3 = 9/2 = 4.5 cm^2
Area of entire figure = 18 cm^2 + 4.5 cm^2 = 22.5 cm^2