Question 263933
Hint: the highest point will be at the vertex of {{{f(x)=160x-16x^2}}}. The vertex is the point (h,k) where {{{h=-b/(2a)}}} and {{{k=f(h)}}}. From the equation {{{f(x)=160x-16x^2}}}, we can see that {{{a=-16}}} and {{{b=160}}}. Plug these values into {{{h=-b/(2a)}}} to find h (the x coordinate of the vertex). Once you have this x value, plug it into {{{f(x)=160x-16x^2}}} to find k (the y coordinate of the vertex).



It turns out that the highest point will be the y coordinate of the vertex. So once you find the y coordinate of the vertex, you will find the highest point.