Question 263782
The sum of three numbers is 105. The third is 11 less than ten times the second. Twice the first is 7 more than three times the second. Find the numbers.

let the second number be x

third = 10x-11

first  = (3x+7)/2

x+10x-11 + (3x+7)/2 = 105

2x+20x-22+3x+7 = 210

25x=225x

x= 9 = second

third = 79

first =17