Question 263671
5z/z-2 - 10/z+2 = 40/z^2 -4
remeber to multiply every thing by a denomenator that will eleminate x from the denominator. this problem requires us to multiply by ((z-2)(z+2))
5z/z-2((z-2)(z+2)) - 10/z+2((z-2)(z+2)) = 40/z^2 -4((z-2)(z+2))
5z(z+2)-10(z-2)=40 subtract 40 and simplify multiplication
5z^2+10z-10z+20-40=0
5z^2-20=0 divide by 5
z^2-4=0
(z-2)(z+2)=0
Z=(-2,2)

Heres the pluggin solver
*[invoke quadratic "x", 5, 0, -20]