Question 263727
Hello, 
First off let's get rid of the fractions by multiplying each (x+1)(x+2) to get:
(x+1)(x+2) + (5)(x+1) = (3)(x+2) This can be expanded out tobe:
x^2+3x+2+5x+5=3x+6  Now combine terms and subtract 3x and 6 from both sides to get 5:
x^2+5x+1=0
Now apply the quadratic equation: {{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }
x = (-5 +- sqrt(21))/2   
There we go!
RJ 
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