Question 263727
(x+1)/(x+1) + (5)/(x+2) = (3)/(x+1) times every thing by ((x+1)(X+2))
((x+1)(x+2))+((5(x+1))= ((3(X+2)) multiply together
(x^2+3x+2)+(5x+5)=(3x+6) add like terms
x^2 + 8x + 7= 3x + 6 Subtract 3x and 6 from both sides
.    -3x - 6 -3x - 6
x^2 +5x+1=0 now u have a quadratic equation
*[invoke quadratic "x", 1, 5, 1]