Question 263713
The equation of the given line to 6x + 3y= 15
Let the equation of the parallel line be 6x + 3y = c ...(1)
This line passe through the point (6,9)
Therefore, 6*6+3*9 = c
]                c = 63
So The equation of the required line is 6x+3y = 63
         3y = -6x+63
         y = -2x+21