Question 263708
d+q=15
10d+25q=275
d=15-q
10(15-q)+25q=275
150-10q+25q=275
15q=125
q=125/15=25/3
we can't have fractional amount for number of coins.
q=15-d
10d+25(15-d)=275
2d+5(15-d)=55
2d+75-5d=55
-3d=-20
d=20/3
again we can't have a fractional number of coins.
Something is wrong with the problem
either 15 is wrong or 275 is wrong