Question 263635
here is the question
{{{((3x-21)/(3x))}}} / {{{((x^2-49)/(x^2+7x))}}}
step 1 - factor each numerator and or denominator to get
{{{((3(x-7))/(3x))}}} / {{{((x+7)(x-7))/(x(x+7)))}}}
step 2 - multiply by the flip of the second big fraction to get
{{{((3(x-7))/(3x))}}} * {{{(x(x+7)/(x-7)(x+7))}}}
step 3 - cancel all like terms to get
{{{1}}}