Question 263578
The original question I think was
(i) {{{(6/2)^x - 49/x = 17}}}
If don't include the (_) then there is no solution. 
if we do include the (_) then we get an answer.
we can express (i) as
(ii) {{{3^x - 49/x = 17}}}
through some calculator manipulations, we get
x ~ -2.88946
If we apply this to the left hand side, we get
17.0000053 ~ 17.