Question 263488
You note that the values are all divisible evenly by 2 (that is, there is no remainder).  So the number 2 is part of the pattern...after you get past the starting 1.
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Of we know that {{{2^0}}} (for that matter, any number 'x' raised to the zeroth power) = 1.
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And {{{2^1}}} = 2.
{{{2^2}}} = 4.
{{{2^3}}} = 8.
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So that seems to match the pattern.  The next in the sequence would likely be:
{{{2^4}}} = 16.
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