Question 263369
here is the original equation
{{{2x^2 - 2x + 3 = 0}}}
step 1 - using quadratic, we get
{{{x = (2 +- sqrt(4-4*2*3))/(4)}}}
and then 
{{{x = (2 +- sqrt(-20))/(4)}}}
simplifying the radical, we get
{{{x = (2 +- 2isqrt(5))/(4)}}}
and canceling, we get
{{{x = (1 +- isqrt(5))/(2)}}}