Question 263370
here is our original equation:
{{{z + 4 + 12/z = 0 }}}
step 1 - multiply by z to get
{{{z^2 + 4z + 12 = 0}}}
using the quadratic, we get
{{{x = (-4 +- sqrt(16-4*1*12))/(2)}}}
which becomes
{{{x = (-4 +- sqrt(-32))/(2)}}}
and then
{{{x = (-4 +- 4isqrt(2))/(2)}}}
canceling, we get
{{{x = -2 +- 2isqrt(2)}}}