Question 263236
The manager of a mens clothing store sold out of the entire stock of $60 jackets and $50 dollar jackets for a total of $3080. If the manager sold 22 more $50 dollar jackets than $60 dollar jackets. How many jackets of each were sold?

Let the number of $60 jacket sold be x
So the number of $50 jackets sold will be x+22

60*x+(x+22)*50 = 3080

60x+50x+1100= 3080
110x= 3080-1100=1980
X= 18 ---- $60 jacket
Y=x=22 = 18+22= 40---- $50 jacket

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