Question 263183
step 1 - set = 0 as follows:
{{{2x^2-3x + 7 = 0}}}
step 2 - using quadratic formula, we get
{{{x = (3 +- sqrt(9-4*2*7 ))/(4)}}}
and then
{{{x = (3 +- sqrt(-47))/(4)}}}
which gives us the following imaginary roots:
{{{x = (3 +- isqrt(47))/(4)}}}