Question 263161
the length of one leg of a right triangle is 10 ft. the length of the hypotenuse is 2 feet longer than the other leg. find the length of the hypotenuse and the other leg

let the other leg be x

one leg =10

length of hypotenuse  x+2

x^2+10^2=(x+2)^2

x^2+100=x^2+4x+4

4x=100-4
X= 100-4/   4

X= 24

Hypotenuse= 26