Question 263177
here is the original expression:
(i) {{{x/(x^2-25) + 5/x }}}
we can get a common denominator as: x(x-5)(x+5) we get
(ii) {{{(x^2+5x^2-125)/(x*(x-5)(x+5))}}}
simplified, we get
(iii) {{{(x^2+5x^2-125)/(x^3-25x^2)}}}