Question 263162
Given, in triangle ABC, angle B is 5 times angle A and angle C is 14 degrees less than 4 times angle A
So, B = 5A and C = 4A-14
But we know A+B+C = 180
            A+5A+4A-14 = 180
            10A = 194
            A = 194/10 = 19.4
            B = 5A = 5*19.4 = 97
            C = 4A-14= 4*19.4-14 = 63.6