Question 263134
I assume the original equation was
(i) {{{(2/5)x + (1/3) (x-4) = (1/5) (x-3)}}}
step 1 - multiply by 15 to get
(ii) {{{6x + 5(x-4) = 3(x-3)}}}
step 2 - distribute to get
(iii) {{{6x + 5x - 20 = 3x - 9}}}
step 3 - combine like terms to get
(iv)  {{{11x - 20 = 3x - 9}}}
step 4 - subtract 3x and add 20 to get
(vi) {{{8x = 11}}}
divide to get
 x = 11/8