Question 263095
Hint: If we let {{{z=x^(-2)}}}, then {{{z^2=x^(-4)}}}. Now apply the proper substitutions to get {{{2z^2-10z+2=0}}}. Now use the quadratic formula to solve {{{2z^2-10z+2=0}}} and get solutions in terms of 'z'. Once you have those solutions, plug them into {{{z=x^(-2)}}} to find solutions in terms of 'x'.