Question 263007
{{{h(x)=x^2-5x}}}
A good thing to remember is that the
vertex and axis of symmetry are half-way
between the roots (solutions for {{{h(x) = 0}}})
{{{x^2 - 5x = 0}}}
{{{x*(x - 5) = 0}}}
The solutions are {{{x = 0}}},{{{x = 5}}}
Half-way between is {{{x = 5/2}}}
Now solve for {{{h(x)}}}
{{{h(x) = (5/2)^2 - 5*(5/2)}}}
{{{h(x) = 25/4 - 25/2}}}
{{{h(x) = 25*(1/4 - 2/4)}}}
{{{h(x) = -25/4}}}
So, the vertex is at (5/2, -25/4)
The axis of symmetry is {{{x = 5/2}}}
{{{ graph( 500, 500, -3, 8, -8, 8, x^2 - 5x) }}}