Question 32929
(4x-1)/(x~2+5x-7)=1/(x-2)-2/(x+7) or (4x-1)/(x+7)(x-2)=1/(X-2)-2/(X+7) OR

(4X-1)/(X+7)(X-2)=((X+7)-(2X+4))/(X+7)(X-2) or 4x-1=x+7-2x+4 or 5x=12 or x=12/5

proof (4(12/5)-1)/(12/5)~2+5(12/5)-7=1/((12/5)-2)-2/((12/5+7) or
(48/5-1)/((12/5)~2+(12/5)+7)=1/((12/5)-2)-2/((12/5)+7) or 43/5=12/5+7-2(12/5)+4 
or 43/5=12/5+7-24/5+4 or 43/5=12/5+11-24/5 or 43/5=-12/5+11 or 55/5=11 or 11=11

y=-5x-2
y=-3x substituting y=-3x in equation #1 we get
-3x=-5x-2 or 2x=-2 or x=-1 then y=-5(-1)-2 or y=+5-2 or y=3

proof 3=-3(-1) or 3=3 and 3=-5(-1)-2 or 3=5-2 or 3=3

3x-y=5
-4x+y=-5 adding these two equztions we get
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-x=0 substituting 0 for y in equation #1 we get
3*0-y=5 or y=-5 
proof -4*0-5=-5 or -5=-5 and 3*0-(-5)=5 or 5=5

2x-y=-1
2x+z=-6
3y-z=7 adding equation #2 & #3 we get
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2x+3y=1 subtracting this equation from equztion #1 we get
2x-y=-1
-2x-3y=-1
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-4y=-2 or y=1/2 then 2x-(1/2)=-1 or 2x=-1/2 or x=-1/4 therefore 3(1/2)-z=7 or
3/2-z=7 or -z=7-3/2 or z=-11/2
x=-1/4, y=1/2 & z=-11/2