Question 262954
A Chemist has two solutions of alcohol. One has a 24% concentration and the other has a 40% solution. How many liters of EACH solution must be mixed to obtain 120 liters of a 30% solution?

Soln1	soln2	mix
24%	40%	30%
X	120-x	120

0.24x+0.4(120-x)=0.3*120

0.24x+48-0.4x=36
-0.16x=-12
X=12/0.16

X= 75 liters the other will be 45 liters