Question 262876
A certain two-digit number has a value that is 2 more than 6 times the sum of its digits. The tens digit is 1 more than the units digit. Find the number by using linear sytems.

Let the digit in tens place be x
And that in the units place be y

10x+y=6(x+y) +2

X=y+1


10x+y = 6x+6y+2
4x-5y=2 -------------1
x-y=1 ----------------2

multiply eq 2 by 4 and subtract the equations
4x-4y=4
4x-5y=2

Y=2
X=3
The number  is  31