Question 262881
{{{log(3,7x) = log(3,2x + .05)}}}
I can use the general rule
if
(1) {{{log(a,b) = log(a,c)}}}
then
(2) {{{b = c}}}
To show this, rewrite (1) as
{{{y = log(a,b)}}}
{{{y = log(a,c)}}}
then
{{{a^y = b}}}
{{{a^y = c}}}
so, {{{b = c}}}
therefore
{{{7x = 2x + .05}}}
{{{5x = .05}}}
{{{x = .01}}}
check answer:
{{{log(3,7x) = log(3,2x + .05)}}}
{{{log(3,7*.01) = log(3,2*.01 + .05)}}}
{{{log(3,.07) = log(3,.07)}}}
OK