Question 32905
{{{(log(x)^2)/log(y)^2 = (log(x))/log(y)}}}?
Apply the power rule for logarithms: {{{Log(M)^p = pLog(M)}}}

{{{log(x)^2 = 2log(x)}}} and
{{{log(y)^2 = 2log(y)}}}, so,

{{{(log(x^2))/log(y)^2 = (2log(x))/2log(y)}}} Cancel the 2's to get:
{{{log(x)/log(y)}}}

The answer is: True!