Question 262828
The equation of a circle can be expressed as
{{{(x-h)^2 + (y-k)^2 = r^2}}}
we know the center, so we have
{{{(x+2)^2 + (y)^2 = r^2}}}
the distance from the center to the point on the circle is 4. This is also called radius. SO, we get
{{{(x+2)^2 + (y)^2 = 4^2}}}