Question 262790
First we must put this equation into vertex form. To do that we need to complete the square. I will jump right to vertex form as
{{{y = (x-2)^2-5}}}
Now, we have the vertex as (2, -5)
line of symmetry is the x-value of the vertex or x = 2.
Since the equation starts with (+), then the minimum will be at the vertex at (2,-5)
here is the graph
 
{{{ graph( 300, 200, -10, 10, -10, 10, x^2-4x-1) }}}