Question 262669
A Chemist has two solutions of alcohol. one has a 24% concentration and the other has 40% concentration. How many liters of each solution must be mixed to obtain 120 liters of a 30% solution?

24%---------40%----------30%

X------------120-x--------120

0.24x+0.4(120-x)=0.3*120

0.24x + 48 – 0.4x=36
-0.16x=-12
X=75 liters
120-75=45 liters

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