Question 262512
Find three consecutive positive even integers such that the product of the second and third integers is twenty more than ten times the first integer.

Let x be the smallest of the three consecuticve even integers. Then the second and third integers are x+2 and x+4 respectively.

Then we have:

(x+2)*(x+4) = 10*x + 20

Solve the above for x and then calculate x+2 and x+4.