Question 32726
Solve:
{{{x^3+10x^2+26x = 0}}} Factor an x.
{{{x(x^2+10x+26) = 0}}} Apply the zero products principle.
{{{x = 0}}} and/or {{{x^2+10x+26 = 0}}}
Solve:
{{{x^2+10x+26 = 0}}} Solve using the quadratic formula:{{{x=(-b+-sqrt(b^2-4ac))/2a}}} 
{{{x=(-10+-sqrt(10^2-4(1)(26)))/2(1)}}}
{{{x=(-10+-sqrt(100-104))/2}}}
{{{x=(-10+-sqrt(-4))/2}}}
{{{x=-5+-sqrt(-1)}}}

The roots are:
x = 0
x = -5+i or -(5-i)
x = -5-i or -(5+i)