Question 262357
D=RT
455=(R+R+10)3.5
455=(2R+10)3.5
455=7R+35
7R=455-35
7R=420
R=420/7
R=60 MPH IS THE RATE OF THE SLOWER CAR.
60+10=70 MPH IS THE RATE FOR THE FASTER CAR.
PROOF:
455=(60+70)*3.5
455=130*3.5
455=455