Question 262347
 I am working in week eight of math 116. I am on problem 13 which the first part is a numberline graph. I was asked to choose the compound inequality, which I was able to do. However the second part of the question askes me to write the solution in interval notation. The problem is x<9 and x>=-6. Does anyone know how to do this problem? If so I really need some help. 
<pre><font size = 4 color = "indigo"><b>
{{{matrix(1,3,x<9, and, x>=-6)}}}

Now {{{x>=-6}}} can be written as {{{-6<=x}}}

Now you have

{{{matrix(1,3,x<9, and, -6<=x)}}}

Reverse these:

{{{matrix(1,3,-6<=x, and, x<9)}}}

Now you can write these together as a continued inequality
like this:

{{{-6<=x<9}}}

That says x is between -6 and 9, INclusive of -6,
but EXclusive of 9, so on a number line the graph is

-------@============================================o---------
-8 -7 -6 -5 -4 -3 -2 -1  0  1  2  3  4  5  6  7  8  9 10 11 12

Notice that there is a closed circle at -6 and an open circle
at 9.  The interval notation is an abbreviation of the above
graph.  The left endpoint is -6 and the right endpoint is 9,
so the interval notation is 

         [-6,9)

The bracket "[" on the left next to the -6 indicates that the -6
is included, the parentheses ")" on the right indicates that the
9 is NOT included. 

Edwin</pre>