Question 262355
<font face="Garamond" size="+2">

Let *[tex \Large x] represent the short piece.  Then the middle-sized piece is *[tex \Large x\ -\ 1] and the long piece is *[tex \Large 2x].  The measures of the  three pieces must add up to 29, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ \left(x\ +\ 1\right)\ +\ 2x\ =\ 29]


Solve for *[tex \Large x] to get the measure of the short piece.  Add 1 to get the measure of the middle piece and double the value of *[tex \Large x] to get the measure of the long piece.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>