Question 262353
The first thing we need to determine here is the slope of the line.  Remember that if you have two points (x1,y1) and (x2,y2), the slope is:

{{{m = (y2-y1)/(x2-x1)}}}

So here, (x1,y1) is (6,-4) and (x2,y2) is (3,2), so the slope is:

{{{m = (2-(-4))/(3-6) = 6/-3 = -2}}}

Now, remember that if you have a point (x1,y1) and a slope m, the equation of the line is:

y-y1 = m(x-x1)

So we have

y-(-4) = -2(x-6)

y+4 = -2x+12

y = -2x + 8