Question 262264
{{{x^2y+yx^2=6}}}
{{{2x^2y=6}}}
{{{x^2y=3}}}
{{{y=3x^(-2)}}}
{{{dy/dx=3(-2x^(-3))}}}
{{{dy/dx=-6x^(-3))}}}
{{{d2y/dx2=-6(-3x^(-4))}}}
{{{d2y/dx2=18x^(-4)}}}
At x=1
{{{d2y/dx2=18}}}
E) is the correct answer.