Question 262261
Here is the problem
{{{4096^(-5/6)}}}
step 1 - we can take the 6th root of 4096 as
{{{4096^(1/6)}}}
we can rewrite 4096 as 2^12, so we get
{{{(2^12)^(1/6)}}}
using rules of exponents, we get
{{{2^2}}} = 4
so, {{{4096^(1/6)}}} is really 4.
step 2 - convert the negative into a positive as
{{{4^(-5)}}} = {{{(1/4)^5}}}
expand this base to get
{{{1/1024}}}