Question 262208
area = (1/2)bh
so we can say
{{{A = (1/2)bh}}}
b = h so
{{{A = (1/2)b^2}}}
multiply by 2 and we get
{{{2A = b^2}}}
taking a square root we get
{{{sqrt(2A) = b}}}
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we are told that A = 17. We get
{{{sqrt(2*17) = b}}}
{{{sqrt(34) = b}}}
So, b ~ 5.83, 
but to the nearest whole number, we get
 b = 6.