Question 262214
Let the speed of a beetle = x cm/s
Then,the speed of the ant = x+1 cm/s
Given, from points that are 50cm apart the ant and the beettle start walking directly towards each other and meet in 10 secs.
speed*time = distance
(x+x+1)*10 = 50
Dividing by 10,
 2x+1 = 5
 2x = 5-1
 2x = 4
 x = 2  
Therefore, the speed of a beetle = 2 cm/s
And,the speed of the ant = 2+1 = 3 cm/s