Question 262214
This is an RTD question. Here is a table based on the above information:
animal . . . . . . ..rate . . . . . . . . .time . . . . . .. . .distance
ant . .. . . . . . . . b+1. . . . . . . . .10. . . . . . . . . . . . . .10b + 10
beetle. . . . . . . .b. . . . . . . . . . . .10. . . . . . . . . . . . .10b
total. . . . . . . . .. . . . . . . . .. . . . . . . . .. . . . . . . . . . . . 50
looking at the third column, we have
{{{10b + 10 + 10b = 50}}}
combine like terms to get
{{{20b + 10 = 50}}}
subtract to get
 {{{20b = 40}}}
divide to get
{{{b = 2}}}
{{{b+1= 3}}}
ant walks 3 cm/s
beetle walks 2 cm/s