Question 262207
Let the length = x
Given, the width of a certain rectangle is 2 inches more than one fourth of its length.
So, width = x/4 +2
Perimeter is 2*(x+x/4+2) = 54
             2x+x/2+4 = 54
             (4x+x)/2 = 54-4
              5x = 2*50
              5x = 100
              x = 100/5
              x = 20 inches
Therefore  the length = 20
               width = x/4+2 = 20/4+2 = 5+2 = 7 inches