Question 262168
The tens digit of a two digit number is 3 times greater than the units digit.  Eight times the sum of the digits is 1 less than the number.  Find the number.

I've been provided the answer and have ran through numerous equations, but can't seem to get the correct equation that solves for the answer.

I appreciate any help you can provide...


Let the units digit be x   .
The tens digit will be 3x

Eight times the sum = 8*(x+3x) 

1 less than the number = 30x+x -1

8*(x+3x) = 30x +x -1

32x = 31x-1
x=-1
tens digit =-3  The number is -31


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