Question 261891
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Sorry, not <i>inte<b>r</b>gers</i>, rather they are <i>integers</i>.


Your beginning is exactly correct.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ (-3)\ =\ -\frac{3}{2}\left(x\ -\ 2\right)]


Multiply both sides by 2:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2y\ +\ 6\ =\ -3\left(x\ -\ 2\right)]


Distribute the -3 on the right:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2y\ +\ 6\ =\ -3x\ +\ 6]


Add *[tex \Large 3x\ -\ 6] to both sides:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x\ +\ 2y\ =\ 0]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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