Question 261891
A line perpendicular to y=2/3x+5 (2,-3)
(y = (2/3)x + 5 would be better)
The slope of the given line is 2/3
Lines perpendicular to it have a slope of -3/2, the negative inverse.
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Find the equation of the line thru (2,-3) with a slope of -3/2.
Use y = mx + b and the point to find b:
-3 = (-3/2)*2 + b
b = 0
--> y = -3x/2