Question 261847
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<b>Step 1:</b>  Determine the slope of the given line by inspection of the coefficient on *[tex \LARGE x] after putting the equation into slope-intercept, that is *[tex \LARGE y\ =\ mx\ +\ b], form.


<b>Step 2:</b>  Use the fact that perpendicular lines have slopes that are negative reciprocals of each other, that is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  L_1\ \perp\ L_2 \ \ \Leftrightarrow\ \ m_1\ =\ -\frac{1}{m_2}\ \text{ and } m_1,\, m_2\, \neq\, 0]


to determine the slope of the desired line.


<b>Step 3:</b> Use the slope determined in step 2 and the given point in the point-slope form of the equation of a line to write the desired equation.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ m(x\ -\ x_1)]



<b>Step 4:</b> Follow your textbook's or instructor's instructions, if any, as to the final form of your answer, i.e. standard form, slope-intercept form, etc.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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